fopen incompatible type char (*)[9] instead of char(*) in C

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My program in C reads data in a file
in order to initialise variables but it won't open the file. It fails when it reaches
fopen. Xcode outputs the following warning for both fopen and printf. I understand the
error but I don't know how to correct it, I tried many tricks but it won't do, can
anyone help me out ? I just want my program to open
Try1.txt.

Incompatible
pointer types passing 'char (*)[9]' to parameter of type const
char*'

So this is the code inside my
main function :

FILE *infile =
            NULL;
const char infilename [] = "Try1.txt";

infile =
            fopen(&infilename, "r");
if (infile ==
            NULL)

{
 printf("Failed to open file: %s\n",
            &infilename);
 return
            1;
}

Note
that the program stops before reaching the if loop because it never prints. I tried to
initialise the size and to add '\0' at the end of my string too.

Answer

It's because of
&infilename, which gives you a pointer to the array of
characters. Drop the address-of operator and it will work.