python - Python3 - Generate string matching multiple regexes, without modifying them

itemprop="text">

I would like to generate string
matching my regexes using Python 3. For this I am using handy library called href="https://bitbucket.org/leapfrogdevelopment/rstr/" rel="nofollow
noreferrer">rstr.

• ^[abc]+.


• [a-z]+

I
must find a generic way, how to create string that would match both my
regexes.

Modify
both regexes or join them in any way. This I consider as ineffective solution,
especially in the case if incompatible
regexes:

import
            re
import rstr

regex1 =
            re.compile(r'^[abc]+.')
regex2 =
            re.compile(r'[a-z]+')


for index in range(0,
            1000):
 generated_string = rstr.xeger(regex1)
 if
            re.fullmatch(regex2, generated_string):
 break;
else:

            raise Exception('Regexes are probably
            incompatibile.')

print('String matching both regexes is:
            {}'.format(generated_string))

Is
there any workaround or any magical library that can handle this? Any insights
appreciated.

Asker
already has the string, which he just want to check against
multiple regexes in the most elegant way. In my case we need to
generate string in a smart way that would match
regexes.

Answer

I solved this using a little alternative
approach. Notice second regex is basically insurance so only lowercase letters are
generated in our new string.

I used
Google's python package sre_yield which allows charset limitation. Package is also
available on PyPi. My
code:

import
            sre_yield
import string

sre_yield.AllStrings(r'^[abc]+.',
            charset=string.ascii_lowercase)[0]
# returns
            `aa`