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I need to implement a prefix sum
algorithm and would need it to be as fast as possible.
/>Ex:
[3, 1, 7, 0, 4, 1, 6,
3]
should
give:
[3, 4, 11, 11, 15, 16, 22,
25]
Is there a way to
do this using SSE SIMD CPU instruction?
My first
idea is to sum each pair in parallel recursively until all sum have been computed like
below!
//in parallel do
for (int i = 0; i < z.length; i++) {
z[i] = x[i
<< 1] + x[(i << 1) +
1];
}
To
make the algorithm a little bit more clear, z
is not the final
output, but instead used to compute the
output.
int[] w =
computePrefixSum(z);
for (int i = 1; i < ouput.length; i++) {
ouput[i] = (i % 2 == 0) ? (x[i] + ouput[i - 1]) : w[(i - 1) >>
1];
}
The fastest parallel prefix sum algorithm I
know of is to run over the sum in two passes in parallel and use SSE as well in the
second pass.
In the first pass you calculate
partial sums in parallel and store the total sum for each partial sum. In the second
pass you add the total sum from the preceding partial sum to the next partial sum. You
can run both passes in parallel using multiple threads (e.g. with OpenMP). The second
pass you can also use SIMD since a constant value is being added to each partial
sum.
Assuming n
elements of an array, m
cores, and a SIMD width of
w
the time cost should
be
n/m + n/(m*w) =
(n/m)*(1+1/w)
Since
the fist pass does not use SIMD the time cost will always be greater than
n/m
For example for
four cores with a SIMD_width of 4 (four 32bit floats with SSE) the cost would be
5n/16
. Or about 3.2 times faster than sequential code which has
a time cost of n
. Using hyper threading the speed up will be
greater still.
In special cases it's possible to
use SIMD on the first pass as well. Then the time cost is
simply
2*n/(m*w)
I
posted the code for the general case which uses OpenMP for the threading and intrinsics
for the SSE code and discuss details about the special case at the following
link
href="https://stackoverflow.com/questions/19494114/parallel-prefix-cumulative-sum-with-sse">parallel-prefix-cumulative-sum-with-sse
Edit:
I
managed to find a SIMD version for the first pass which is about twice as fast as
sequential code. Now I get a total boost of about 7 on my four core ivy bridge
system.
Edit:
For larger arrays one problem is that after the first pass most values have
been evicted from the cache. I came up with a solution which runs in parallel inside a
chunk but runs each chunk serially. The chunk_size
is a value
that should be tuned. For example I set it to 1MB = 256K floats. Now the second pass is
done while the values are still inside the level-2 cache. Doing this gives a big
improvement for large arrays.
Here is
the code for SSE. The AVX code is about the same speed so I did not post it here. The
function which does the prefix sum is
scan_omp_SSEp2_SSEp1_chunk
. Pass it an array
a
of floats and it fills the array s
with the cumulative sum.
__m128
scan_SSE(__m128 x) {
x = _mm_add_ps(x,
_mm_castsi128_ps(_mm_slli_si128(_mm_castps_si128(x), 4)));
x = _mm_add_ps(x,
_mm_shuffle_ps(_mm_setzero_ps(), x, 0x40));
return
x;
}
float pass1_SSE(float *a, float *s, const int n)
{
__m128 offset = _mm_setzero_ps();
#pragma omp for
schedule(static) nowait
for (int i = 0; i < n / 4; i++) {
__m128 x = _mm_load_ps(&a[4 * i]);
__m128 out = scan_SSE(x);
out = _mm_add_ps(out, offset);
_mm_store_ps(&s[4 * i], out);
offset = _mm_shuffle_ps(out, out, _MM_SHUFFLE(3, 3, 3, 3));
}
float tmp[4];
_mm_store_ps(tmp, offset);
return
tmp[3];
}
void pass2_SSE(float *s, __m128 offset, const
int n) {
#pragma omp for schedule(static)
for (int i = 0;
i __m128 tmp1 = _mm_load_ps(&s[4 * i]);
tmp1 =
_mm_add_ps(tmp1, offset);
_mm_store_ps(&s[4 * i], tmp1);
}
}
void scan_omp_SSEp2_SSEp1_chunk(float a[],
float s[], int n) {
float *suma;
const int chunk_size =
1<<18;
const int nchunks = n%chunk_size == 0 ? n / chunk_size : n /
chunk_size + 1;
//printf("nchunks %d\n", nchunks);
#pragma omp
parallel
{
const int ithread =
omp_get_thread_num();
const int nthreads =
omp_get_num_threads();
#pragma omp single
{
suma = new float[nthreads + 1];
suma[0] = 0;
}
float offset2 = 0.0f;
for (int c = 0; c < nchunks;
c++) {
const int start = c*chunk_size;
const int chunk
= (c + 1)*chunk_size < n ? chunk_size : n - c*chunk_size;
suma[ithread +
1] = pass1_SSE(&a[start], &s[start], chunk);
#pragma omp
barrier
#pragma omp single
{
float tmp = 0;
for (int i = 0; i < (nthreads + 1); i++) {
tmp += suma[i];
suma[i] = tmp;
}
}
__m128 offset =
_mm_set1_ps(suma[ithread]+offset2);
pass2_SSE(&s[start], offset,
chunk);
#pragma omp barrier
offset2 = s[start +
chunk-1];
}
}
delete[]
suma;
}
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