python division precision

I am aware of floating point being inaccurate and would like to know
the best way to get 0.08354 instead of
(0.08353999999999999) when I do the following in
Python:

d =
            8.354/100

print (d)

Answer

Use the builtin
round()
function:

>>> d =
            8.354/100
>>> d
0.08353999999999999
>>>
            round(d, 6)
0.08354
>>>