What exactly does putting
extern "C"
into C++ code
do?
For
example:
extern "C"
{
void foo();
}
What exactly does putting
extern "C"
into C++ code
do?
For
example:
extern "C"
{
void foo();
}
Answer
extern "C" makes a function-name in C++ have
'C' linkage (compiler does not mangle the name) so that client C code can link to (i.e
use) your function using a 'C' compatible header file that contains just the declaration
of your function. Your function definition is contained in a binary format (that was
compiled by your C++ compiler) that the client 'C' linker will then link to using the
'C' name.
Since C++ has overloading of function
names and C does not, the C++ compiler cannot just use the function name as a unique id
to link to, so it mangles the name by adding information about the arguments. A C
compiler does not need to mangle the name since you can not overload function names in
C. When you state that a function has extern "C" linkage in C++, the C++ compiler does
not add argument/parameter type information to the name used for
linkage.
Just so you know, you can
specify "C" linkage to each individual declaration/definition explicitly or use a block
to group a sequence of declarations/definitions to have a certain
linkage:
extern "C" void
foo(int);
extern "C"
{
void g(char);
int
i;
}
If
you care about the technicalities, they are listed in section 7.5 of the C++03 standard,
here is a brief summary (with emphasis on extern
"C"):
I want to output an inline jpg image as a base64 encoded string, however when I do this : $contents = file_get_contents($filename); print &q...
No comments:
Post a Comment