inheritance - How do you declare an interface in C++?

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How do I setup a class that represents
an interface? Is this just an abstract base class?

Answer

To expand on the answer by href="https://stackoverflow.com/questions/318064/how-do-you-declare-an-interface-in-c#318084">bradtgmurray,
you may want to make one exception to the pure virtual method list of your interface by
adding a virtual destructor. This allows you to pass pointer ownership to another party
without exposing the concrete derived class. The destructor doesn't have to do anything,
because the interface doesn't have any concrete members. It might seem contradictory to
define a function as both virtual and inline, but trust me - it
isn't.

class
            IDemo
{
 public:

 virtual ~IDemo()
            {}
 virtual void OverrideMe() = 0;
};

class
            Parent
{
 public:
 virtual
            ~Parent();
};


class Child : public Parent,
            public IDemo
{
 public:
 virtual void
            OverrideMe()
 {
 //do stuff

            }
};

You
don't have to include a body for the virtual destructor - it turns out some compilers
have trouble optimizing an empty destructor and you're better off using the default.