json - Print before and after each record in awk

I am trying to convert LDIF to JSON using awk.

Can't figure out how to print before and after each multi-line record. Can print in BEGIN and END one time each or before and after each line. But never before and after each record.

Actual LDIF input to awk is:

dn: CN=foo
objectClass: top

dn: CN=bar
objectClass: top

To convert to JSON awk needs output to look like this:

{
  "dn": "CN=foo",
  "objectClass": "top"
}
{
  "dn": "CN=bar",

  "objectClass": "top"
}

Script 1 wraps each line of the record with curly braces.

BEGIN {                                                                                                                                                        
        RS="\n\n#";
        FS=": ";
}

print "{"
{
        print "\""$1"\": \""$2"\",";
}
print "}"

Script 2 wraps the set of all records with on set of curly braces:

BEGIN {                                                                                                                                                        

        RS="\n\n#";
        FS=": ";
        print "{"
}
{
        print "\""$1"\": \""$2"\",";
}
END{
        print "}"
}

Seems like awk only has BEGIN, END and implicit loop over records (single or multi-line). I can't figure out how to print something before and after each multi-line record. Is this possible in awk? Is there a better way to convert LDIF to JSON?

What would an awk script, not a one liner, look like that does the LDIF to JSON conversion?