Thursday, 5 December 2019

c++ - "&" meaning after variable type







Trying to understand meaning of "&" in this situation



void af(int& g)
{

    g++;
    cout<}


If you call this function and pass variable name - it will act the same like normal void(int g). I know, when you write &g that means you are passing address of variable g. But what does it means in this sample?

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