c++ - Ambiguous Overload For operator "

I am learning operator overloading in c++ and I want to know the ouput of following code

#include
using namespace std;
class xyz
{
 public:
        int i;
    friend ostream & operator<<( ostream & Out , int);
};
ostream & operator<<(ostream & out , int i)
{
    cout<<10+i<}
int main()
{
    xyz A;
    A.i=10;
    cout<<10;
}

And i got two errors

1. error: ambiguous overload for ‘operator<<’ (operand types are ‘std::ostream {aka std::basic_ostream}’ and ‘int’)
   cout<<10+i;




2. error: ambiguous overload for ‘operator<<’ (operand types are ‘std::ostream {aka std::basic_ostream}’ and ‘int’)
   cout<<10;

can anyone explain whats the problem ?

I want to know that what happens if I overload an "<<" operator for printing int with only one parameter int(obvious) and I just want to print an number separately like "cout<<10" int the above mentioned code.
So how compiler will decide that which function should be called when i am trying to print just any integer number.