I was practicing some scenario and find a case:
According to closure bar function should have access to var x so I expected to alert 1 and condition get false due to if(!1) but it alerted undefined and condition get true and second alert is with value 10.
var x = 1;
function bar() {
alert(x);
if (!x) {
var x = 10;
}
alert(x);
}
bar();
So I am confused why it is prompting undefined?
According to hoisting in a particular scope you define a variable anywhere it is considered as defined at top always.
If it is due to hoisting effect it still have to alert 10 instead of undefined.
Answer
Hoisting causes a variable to be declared everywhere in the function, not defined.
On the first line of bar, since there is var x on line 3 of the function, the global x is masked and you see the local x (which is undefined since it hasn't been given a value yet).
On line 3 of bar, you have x = 10 which defines the variable. This is not hoisted.
On line 5, you alert it, and it is now defined.

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