Try this:
awk 'NR==1{sub(/^\xef\xbb\xbf/,"")}{print}' INFILE > OUTFILE
On the first record (line), remove the BOM characters. Print every record.
Or slightly shorter, using the knowledge that the default action in awk is to print the record:
awk 'NR==1{sub(/^\xef\xbb\xbf/,"")}1' INFILE > OUTFILE
1
is the shortest condition that always evaluates to true, so each record is printed.
Enjoy!
-- ADDENDUM --
Unicode Byte Order Mark (BOM) FAQ includes the following table listing the exact BOM bytes for each encoding:
Bytes | Encoding Form
--------------------------------------
00 00 FE FF | UTF-32, big-endian
FF FE 00 00 | UTF-32, little-endian
FE FF | UTF-16, big-endian
FF FE | UTF-16, little-endian
EF BB BF | UTF-8
Thus, you can see how \xef\xbb\xbf
corresponds to EF BB BF
UTF-8
BOM bytes from the above table.
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