Tuesday 3 September 2019

java - SAX XML Parser throwing Null Pointer Exception



I'm trying to write an SAX XML Parser in Java and I keep getting a null pointer exception that I can't seem to figure out how to fix. Here is the stack trace:




Exception in thread "main" java.lang.NullPointerException
at SAXParserExample.endElement(SAXParserExample.java:91)
at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.endElement(Unknown Source)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanEndElement(Unknown Source)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl$FragmentContentDriver.next(Unknown Source)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl.next(Unknown Source)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanDocument(Unknown Source)
at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(Unknown Source)
at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(Unknown Source)
at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(Unknown Source)

at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.parse(Unknown Source)
at com.sun.org.apache.xerces.internal.jaxp.SAXParserImpl$JAXPSAXParser.parse(Unknown Source)
at javax.xml.parsers.SAXParser.parse(Unknown Source)
at javax.xml.parsers.SAXParser.parse(Unknown Source)
at SAXParserExample.parseDocument(SAXParserExample.java:43)
at SAXParserExample.runExample(SAXParserExample.java:29)
at SAXParserExample.main(SAXParserExample.java:107)


Here is the main class for the SAX Parser:




import java.io.IOException;
import java.util.ArrayList;
import java.util.Iterator;
import java.util.List;

import javax.xml.parsers.ParserConfigurationException;
import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;


import org.xml.sax.SAXException;

import org.xml.sax.helpers.DefaultHandler;

public class SAXParserExample extends DefaultHandler{

List myFiles;

private String tempVal;


//to maintain context
private DataRow tempFile;


public SAXParserExample(){
myFiles = new ArrayList();
}

public void runExample() {
parseDocument();

printData();
}

private void parseDocument() {

//get a factory
SAXParserFactory spf = SAXParserFactory.newInstance();
try {

//get a new instance of parser

SAXParser sp = spf.newSAXParser();

//parse the file and also register this class for call backs
sp.parse("./src/filelist.xml", this);

}catch(SAXException se) {
se.printStackTrace();
}catch(ParserConfigurationException pce) {
pce.printStackTrace();
}catch(IOException ie) {

ie.printStackTrace();
}
}

/**
* Iterate through the list and print
* the contents
*/
private void printData(){


System.out.println("No of Files '" + myFiles.size() + "'.");

Iterator it = myFiles.iterator();
while(it.hasNext()) {
System.out.println(it.next().toString());
}
}


//Event Handlers

public void startElement(String uri, String localName, String qName) throws SAXException {
//reset
tempVal = "";
if(qName.equalsIgnoreCase("DATAROW")) {
//create a new instance of Datarow
tempFile = new DataRow();
}
}



public void characters(char[] ch, int start, int length) throws SAXException {
tempVal = new String(ch,start,length);
}

public void endElement(String uri, String localName, String qName) throws SAXException {

if(qName.equalsIgnoreCase("DATAROW")) {
//add it to the list
myFiles.add(tempFile);


}else if (qName.equalsIgnoreCase("ID")) {
tempFile.setID(Integer.parseInt(tempVal));
}else if (qName.equalsIgnoreCase("FILENAME")) {
tempFile.setFileName(tempVal);
}else if (qName.equalsIgnoreCase("SEARCHKEY")) {
tempFile.setSearchKey(tempVal);
}else if (qName.equalsIgnoreCase("DATEADDED")) {
tempFile.setDateAdded(tempVal);
}else if (qName.equalsIgnoreCase("APPLICATIONID")) {
tempFile.setApplicationID(tempVal);

}else if (qName.equalsIgnoreCase("DISPLAYFILENAME")) {
tempFile.setDisplayFileName(tempVal);
}
}

public static void main(String[] args){
SAXParserExample spe = new SAXParserExample();
spe.runExample();
}
}



Here is the DataRow class used in the main class:



public class DataRow {

private String fileName = "", searchKey = "", dateAdded = "", applicationID = "", displayFileName = "";

private int id = 0;


public DataRow(){

}

public DataRow(int id, String fileName, String searchKey, String dateAdded, String applicationID, String displayFileName) {
this.id = id;
this.fileName = fileName;
this.searchKey = searchKey;
this.dateAdded = dateAdded;
this.applicationID = applicationID;

this.displayFileName = displayFileName;

}
public String getFileName() {
return fileName;
}

public void setFileName(String fileName) {
this.fileName = fileName;
}


public int getID() {
return id;
}

public void setID(int id) {
this.id = id;
}

public String getSearchKey() {

return searchKey;
}

public void setSearchKey(String searchKey) {
this.searchKey = searchKey;
}

public String getDateAdded() {
return dateAdded;
}


public void setDateAdded(String dateAdded) {
this.dateAdded = dateAdded;
}

public String getApplicationID() {
return applicationID;
}

public void setApplicationID(String applicationID) {

this.applicationID = applicationID;
}

public String getDisplayFileName() {
return displayFileName;
}

public void setDisplayFileName(String displayFileName) {
this.displayFileName = displayFileName;
}


public String toString() {
StringBuffer sb = new StringBuffer();
sb.append("File Details - ");
sb.append("ID:" + getID());
sb.append(", ");
sb.append("Filename:" + getFileName());
sb.append(", ");
sb.append("Search Key:" + getSearchKey());
sb.append(", ");

sb.append("Date Added:" + getDateAdded());
sb.append(", ");
sb.append("Application ID:" + getApplicationID());
sb.append(", ");
sb.append("Display Filename:" + getDisplayFileName());
sb.append(".");

return sb.toString();
}
}



And here is the XML file I'm attempting to parse:



61TestFile.txt123452012-1-6 9.12.32.0PCISTestFile.txt44TestFile.txt123452012-2-5 14.39.50.0PCISTestFile.txt


The XML file is formatted that way because eventually it's going to be parsing metadata return from a database in the form of a single string.


Answer



I haven't used SAX for quite some time, so may be wrong, but my guess is that that you should use the localName, not the qname here, since there are no qualified names (ie. the names that have some namespace like 'namespace:name') in your XML. Therefore, most probably the qname provided is null and, since you access it for comparison, you get an NPE.




According to the javadoc (http://docs.oracle.com/javase/1.4.2/docs/api/org/xml/sax/helpers/DefaultHandler.html#endElement(java.lang.String, java.lang.String, java.lang.String) ), the qname provided may be empty if it is not available in the XML document.


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