android - how to POST a url Kotlin

Get a url like "http://TEST/Data.php?Name=ABC&Number=12"

Want to post this url ,but not open this link.

Then Name and Number columns will change into ABC & 12.

setOnClickListener:

btn_send.setOnClickListener{

            val i = Intent(Intent.ACTION_VIEW, Uri.parse("http://TEST/Data.php?Name=ABC&Number=12"))
            startActivity(i)

        }

This will open the link in a browser. How can I just post this url but not open it?

with this code my app crushed after click button:

btn_send.setOnClickListener{
            URL(url).readText()
        }

9/18 update----------------------------------

tring OKHTTP but nothing happened

fun get() {
            val client = OkHttpClient()
            val url = URL("http://TEST/Data.php?Name=ABC&Number=12")

            val request = Request.Builder()
                .url(url)
                .build()
            OkHttpClient().newCall(request)


root.btn_submit.setOnClickListener {
            get()
        }

if I change OkHttpClient().newCall(request) into OkHttpClient().newCall(request).execute() app will crush

I think is there a problem when i send request to HTTP which is unsafe cause the error

Answer

You just cannot directly open a POST URL in browser.

You have to use Library like one of the following:

• Retrofit


• Volley


• OkHttp

Or you can open it in WebView like below

WebView webview = new WebView(this);
setContentView(webview);
byte[] post = EncodingUtils.getBytes("Name=ABC&Number=12", "BASE64");
webview.postUrl("http://TEST/Data.php", post);

convert the above code into Kotlin