Why does this return 2 instead of 1? Seems the second "var" is silently ignored.
function foo()
{
var local = 1;
{
var local = 2;
}
return local;
}
foo()
/*
2
*/
I want to output an inline jpg image as a base64 encoded string, however when I do this : $contents = file_get_contents($filename); print &q...
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