Friday, 8 June 2018
java - String Literal and Object Literal comparison
Answer
I come up with the scenario & can't understand the logic behind it ? I understood the first one only, rest two unable to understand ? Please explain how internally it work?
public class Test {
public static void main(String[] args) {
String s = "Karan";
Object o = "Karan";
System.out.println(s.equals(o)); // True
System.out.println(o.equals(s)); // True
System.out.println(s == o); // True
}
}
Subscribe to:
Post Comments (Atom)
php - file_get_contents shows unexpected output while reading a file
I want to output an inline jpg image as a base64 encoded string, however when I do this : $contents = file_get_contents($filename); print ...
-
I would like to split a String by comma ',' and remove whitespace from the beginning and end of each split. For example, if I have ...
-
I got an error in my Java program. I think this happens because of the constructor is not intialized properly. My Base class Program public ...
-
I have a method in repository with this implementation which returns a Task Task > GetAllAppsRequestAsync(); I write the getter which cal...
No comments:
Post a Comment