Saturday, 26 January 2019
exception - PHP try-catch not working
Answer
Answer
try
{
$matrix = Query::take("SELECT moo"); //this makes 0 sense
while($row = mysqli_fetch_array($matrix, MYSQL_BOTH)) //and thus this line should be an error
{
}
return 'something';
}
catch(Exception $e)
{
return 'nothing';
}
However instead of just going to catch part and returning nothing
it shows a warning Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, null given
in the line starting with while
. I have never came up to using exceptions in php, but used them a lot in C# and it seems in PHP they are working differently or, as always, I am missing something obvious.
Answer
You can't handle Warnings/Errors with try-catch blocks, because they aren't exceptions. If you want to handle warnings/errors, you have to register your own error handler with set_error_handler
.
But it's better to fix this issue, because you could prevent it.
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