unix - Bash string explode

My file looks like this:

record=123
date=2012.01.20 10:22

In the bash file I do cat myfile.ini, and then I need to use something like explode, because I need ONLY to grep the 123 numeric record data, and nothing else.

How it can be done in the bash ?

Answer

awk -F'=| ' '/record/ {print $2}'

Substitute "date" for "record" in the command above to get the date (the time would be in $3).

This keys on the names of the variables rather than depending on a regex match of the value. It uses spaces or equal signs as field separators.